LintCode Q166 Nth to Last Node in List in Python

  • Jinhai ZHOU
  • 3 Minutes
  • 2016年11月13日
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"""
Definition of ListNode
class ListNode(object):
def __init__(self, val, next=None):
self.val = val
self.next = next
"""
class Solution:
"""
@param head: The first node of linked list.
@param n: An integer.
@return: Nth to last node of a singly linked list.
"""
def nthToLast(self, head, n):
# write your code here
runner = head
current = head
while n > 0:
runner = runner.next
n -= 1
while runner:
runner = runner.next
current = current.next
return current
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